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標題:

F.2 maths(area)

發問:

find solution for Q.49 圖片參考：http://imgcld.yimg.com/8/n/HA05569145/o/701106040081813873455680.jpg

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• F.3 equaliteral
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最佳解答:

Sum of the area of the shaded crescents = (Area of semicircle with diameter AB) + (Area of semicircle with diameter BC)+ (Area of ΔABC) - (Area of semicircle with diameter AC) = π(AB/2)2 + π(BC/2)2 + (25 cm2) - π(AC/2)2 = (π/4)(AB2 + BC2 - AC2) + (25 cm2) = = (π/4)(AC2 - AC2) + (25 cm2) = 25 cm2

其他解答:

AB^2+BC^2=AC^2 shaded area =pi*(AB/2)^2 *1/2 +pi*(BC/2)^2 *1/2 - pi*(AC/2)^2 *1/2 +25 =pi*1/2 *( (AB^2)/4 + (BC^2)/4 -(AC^2)/4 ) +25 =pi*1/2*(AC^2/4-AC^2/4) +25 =25