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標題:

急! Basic Trigonometry 13Q1

發問:

如果 tan x=tan 130 =tan(180-50) x=180-50 or 360-50 答案是=130 or 310 咁以下幾條又點計 ? 請詳細步驟,不要網址回答. 1. sin x = sin 313 2. sin x = -sin 316 3. cos x = -cos 203 4. cos x = cos 181 5. tan x = tan 316 6. tan x = -tan 27

最佳解答:

Assume that 0° ≤ x ≤ 360° 1. sin x = sin 313° sin x = sin (360° - 47°) sin x = -sin 47° x = (180° + 47°) or x = (360° - 47°) x = 227° or x = 313° ===== 2. sin x = -sin 316° sin x = -sin (360° - 44°) sin x = -(-sin 44°) sin x = sin 44° x = 44° or x = (180° - 44°) x = 44° or x = 136° ===== 3. cos x = -cos 203° cos x = -cos (180° + 23°) cos x = -(-cos 23°) cos x = cos 23° x = 23° or x = (360° - 23°) x = 23° or x = 337° ===== 4. cos x = cos 181° cos x = cos (180° + 1°) cos x = -cos 1° x = (180° - 1°) or x = (180° + 1°) x = 179° or x = 181° ===== 5. tan x = tan 316° tan x = tan (360° - 44°) tan x = -tan 44° x = (180° - 44°) or x = (360° - 44°) x = 136° or x = 316° ===== 6. tan x = -tan 27° x = (180° - 27°) or x = (360 - 27)° x = 153° or x = 333°

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